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Trigonometric Integrals Calculator

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1

Solved example of trigonometric integrals

$\int\sin\left(x\right)^4dx$
2

Apply the formula: $\int\sin\left(\theta \right)^ndx$$=\frac{-\sin\left(\theta \right)^{\left(n-1\right)}\cos\left(\theta \right)}{n}+\frac{n-1}{n}\int\sin\left(\theta \right)^{\left(n-2\right)}dx$, where $n=4$

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}+\frac{3}{4}\int\sin\left(x\right)^{2}dx$

Rewrite the trigonometric expression $\sin\left(x\right)^{2}$ inside the integral

$\frac{3}{4}\int\frac{1-\cos\left(2x\right)}{2}dx$

Take the constant $\frac{1}{2}$ out of the integral

$\frac{3}{4}\cdot \left(\frac{1}{2}\right)\int\left(1-\cos\left(2x\right)\right)dx$

Simplify the expression inside the integral

$\frac{3}{8}\left(\int1dx+\int-\cos\left(2x\right)dx\right)$

Solve the product $\frac{3}{8}\left(\int1dx+\int-\cos\left(2x\right)dx\right)$

$\frac{3}{8}\int1dx+\frac{3}{8}\int-\cos\left(2x\right)dx$

The integral of a constant is equal to the constant times the integral's variable

$\frac{3}{8}x+\frac{3}{8}\int-\cos\left(2x\right)dx$

The integral of a function times a constant ($-1$) is equal to the constant times the integral of the function

$\frac{3}{8}x-\frac{3}{8}\int\cos\left(2x\right)dx$

Apply the formula: $\int\cos\left(ax\right)dx$$=\frac{1}{a}\sin\left(ax\right)+C$, where $a=2$

$\frac{3}{8}x-\frac{3}{8}\cdot \left(\frac{1}{2}\right)\sin\left(2x\right)$

Simplify the expression inside the integral

$\frac{3}{8}x-\frac{3}{16}\sin\left(2x\right)$
3

The integral $\frac{3}{4}\int\sin\left(x\right)^{2}dx$ results in: $\frac{3}{8}x-\frac{3}{16}\sin\left(2x\right)$

$\frac{3}{8}x-\frac{3}{16}\sin\left(2x\right)$
4

Gather the results of all integrals

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}-\frac{3}{16}\sin\left(2x\right)+\frac{3}{8}x$
5

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}-\frac{3}{16}\sin\left(2x\right)+\frac{3}{8}x+C_0$

Final Answer

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}-\frac{3}{16}\sin\left(2x\right)+\frac{3}{8}x+C_0$

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