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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\ln\left(\frac{x^2-9}{x+3}\right)-2\ln\left(x-3\right)$
Learn how to solve simplification of algebraic expressions problems step by step online. Simplify the expression ln(x^2-9)-2ln(x-3)-ln(x+3). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). The difference of the squares of two terms, divided by the sum of the same terms, is equal to the difference of the terms. In other words: \displaystyle\frac{a^2-b^2}{a+b}=a-b.. Combining like terms \ln\left(x-3\right) and -2\ln\left(x-3\right).