ðŸ‘‰ Try now NerdPal! Our new math app on iOS and Android

Simplify the expression $\sqrt{\frac{x^3-y^3}{x+y}\frac{x^2+2xy+y^2}{x^2+xy+y^2}}\frac{x^2-y^2}{4}$

Go!
Symbolic mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

 Final answer to the problem

$\sqrt{\frac{x\left(x^{2}+y^{2}\right)}{x+y}}\frac{\left(x+y\right)\left(x^2-y^2\right)}{4\sqrt{x^2+xy+y^2}}$
Got another answer? Verify it here!

 Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Write in simplest form
• Solve by quadratic formula (general formula)
• Find the derivative using the definition
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

The power of a product is equal to the product of it's factors raised to the same power

$\sqrt{\frac{x^3-y^3}{x+y}}\sqrt{\frac{x^2+2xy+y^2}{x^2+xy+y^2}}\frac{x^2-y^2}{4}$

Learn how to solve simplification of algebraic expressions problems step by step online.

$\sqrt{\frac{x^3-y^3}{x+y}}\sqrt{\frac{x^2+2xy+y^2}{x^2+xy+y^2}}\frac{x^2-y^2}{4}$

Learn how to solve simplification of algebraic expressions problems step by step online. Simplify the expression ((x^3-y^3)/(x+y)(x^2+2xyy^2)/(x^2+xyy^2))^(1/2)(x^2-y^2)/4. The power of a product is equal to the product of it's factors raised to the same power. The trinomial x^2+2xy+y^2 is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial.

 Final answer to the problem

$\sqrt{\frac{x\left(x^{2}+y^{2}\right)}{x+y}}\frac{\left(x+y\right)\left(x^2-y^2\right)}{4\sqrt{x^2+xy+y^2}}$

 Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

 Main Topic: Simplification of algebraic expressions

The simplification of algebraic expressions consists in rewriting a long and complex expression in an equivalent, but much simpler expression. This simplification can be accomplished through the combined use of arithmetic and algebra rules.