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# Simplify the expression $\frac{\frac{x^2-6x+9}{4x^2-1}\left(8x^3-1\right)}{x^2+5x-24}$

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##  Final answer to the problem

$\frac{\left(x-3\right)\left(8x^3-1\right)}{\left(4x^2-1\right)\left(x+8\right)}$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Write in simplest form
• Solve by quadratic formula (general formula)
• Find the derivative using the definition
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
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Multiplying the fraction by $8x^3-1$

$\frac{\frac{\left(x^2-6x+9\right)\left(8x^3-1\right)}{4x^2-1}}{x^2+5x-24}$

Learn how to solve polynomial long division problems step by step online.

$\frac{\frac{\left(x^2-6x+9\right)\left(8x^3-1\right)}{4x^2-1}}{x^2+5x-24}$

Learn how to solve polynomial long division problems step by step online. Simplify the expression ((x^2-6x+9)/(4x^2-1)(8x^3-1))/(x^2+5x+-24). Multiplying the fraction by 8x^3-1. Divide fractions \frac{\frac{\left(x^2-6x+9\right)\left(8x^3-1\right)}{4x^2-1}}{x^2+5x-24} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. The trinomial \left(x^2-6x+9\right) is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula.

##  Final answer to the problem

$\frac{\left(x-3\right)\left(8x^3-1\right)}{\left(4x^2-1\right)\left(x+8\right)}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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◻/◻
/
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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Polynomial long division

In algebra, polynomial long division is an algorithm for dividing a polynomial by another polynomial of the same or lower degree, a generalised version of the familiar arithmetic technique called long division.