# Step-by-step Solution

## Simplify the expression $5\left(\frac{x^2+3x+5}{2x-1}\right)^4\left(\frac{2x^2-2x-13}{4x^2-4x+1}\right)$

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$\frac{5\left(x^2+3x+5\right)^4\left(2x^2-2x-13\right)}{\left(2x-1\right)^4\left(4x^2-4x+1\right)}$

## Step-by-step Solution

Problem to solve:

$5\left(\frac{x^2+3x+5}{2x-1}\right)^4\cdot\frac{2x^2-2x-13}{4x^2-4x+1}$

Choose the solving method

1

The power of a quotient is equal to the quotient of the power of the numerator and denominator: $\displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$

$5\left(\frac{\left(x^2+3x+5\right)^4}{\left(2x-1\right)^4}\right)\left(\frac{2x^2-2x-13}{4x^2-4x+1}\right)$

Learn how to solve simplification of algebraic expressions problems step by step online.

$5\left(\frac{\left(x^2+3x+5\right)^4}{\left(2x-1\right)^4}\right)\left(\frac{2x^2-2x-13}{4x^2-4x+1}\right)$

Learn how to solve simplification of algebraic expressions problems step by step online. Simplify the expression 5((x^2+3x+5)/(2x-1))^4*(2x^2-2x-13)/(4x^2-4x+1). The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. Multiplying fractions \frac{\left(x^2+3x+5\right)^4}{\left(2x-1\right)^4} \times \frac{2x^2-2x-13}{4x^2-4x+1}. Multiplying the fraction by 5.

$\frac{5\left(x^2+3x+5\right)^4\left(2x^2-2x-13\right)}{\left(2x-1\right)^4\left(4x^2-4x+1\right)}$
SnapXam A2

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$5\left(\frac{x^2+3x+5}{2x-1}\right)^4\cdot\frac{2x^2-2x-13}{4x^2-4x+1}$