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Simplify the expression $\left(3x+5\right)\left(2x+3\right)$

Step-by-step Solution

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Final answer to the problem

$6x^2+19x+15$
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Step-by-step Solution

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1

Multiply the single term $2x+3$ by each term of the polynomial $\left(3x+5\right)$

$3x\left(2x+3\right)+5\left(2x+3\right)$
2

Multiply the single term $5$ by each term of the polynomial $\left(2x+3\right)$

$3x\left(2x+3\right)+2\cdot 5x+3\cdot 5$
3

Multiply $2$ times $5$

$3x\left(2x+3\right)+10x+3\cdot 5$
4

Multiply $3$ times $5$

$3x\left(2x+3\right)+10x+15$
5

Solve the product $3x\left(2x+3\right)$

$\left(6x+9\right)x+10x+15$
6

Multiply the single term $x$ by each term of the polynomial $\left(6x+9\right)$

$6x\cdot x+9x+10x+15$
7

When multiplying two powers that have the same base ($x$), you can add the exponents

$6x^2+9x+10x+15$
8

Combining like terms $9x$ and $10x$

$6x^2+19x+15$

Final answer to the problem

$6x^2+19x+15$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

FactorFactor by completing the squareFind the integralFind the derivativeFind (3x+5)(2x+3) using the definitionSolve by quadratic formula (general formula)Find the rootsFind break even pointsFind the discriminant

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Plotting: $6x^2+19x+15$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Simplification of algebraic expressions

The simplification of algebraic expressions consists in rewriting a long and complex expression in an equivalent, but much simpler expression. This simplification can be accomplished through the combined use of arithmetic and algebra rules.

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