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Rewrite the fraction $\frac{x}{x^2-3x-4}$ inside the integral as the product of two functions: $x\frac{1}{x^2-3x-4}$
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$\int x\frac{1}{x^2-3x-4}dx$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int(x/(x^2-3x+-4))dx. Rewrite the fraction \frac{x}{x^2-3x-4} inside the integral as the product of two functions: x\frac{1}{x^2-3x-4}. We can solve the integral \int x\frac{1}{x^2-3x-4}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.