Step-by-step Solution

Find the integral $\int\frac{x}{\sqrt{16-x^2}}dx$

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Final Answer

$-\sqrt{16-x^2}+C_0$
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Step-by-step Solution

Problem to solve:

$\int\frac{x}{\sqrt{16-x^2}}dx$

Choose the solving method

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We can solve the integral $\int\frac{x}{\sqrt{16-x^2}}dx$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $16-x^2$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part

$u=16-x^2$

Learn how to solve integrals of rational functions problems step by step online.

$u=16-x^2$

Unlock this full step-by-step solution!

Learn how to solve integrals of rational functions problems step by step online. Find the integral int(x/((16-x^2)^0.5))dx. We can solve the integral \int\frac{x}{\sqrt{16-x^2}}dx by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that 16-x^2 it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part. Now, in order to rewrite dx in terms of du, we need to find the derivative of u. We need to calculate du, we can do that by deriving the equation above. Isolate dx in the previous equation. Substituting u and dx in the integral and simplify.

Final Answer

$-\sqrt{16-x^2}+C_0$
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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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