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# Find the integral $\int\frac{x^3}{\sqrt{x^2+4}}dx$

## Step-by-step Solution

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###  Solution

$\frac{1}{3}\sqrt{\left(x^2+4\right)^{3}}-4\sqrt{x^2+4}+C_0$
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##  Step-by-step Solution 

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We can solve the integral $\int\frac{x^3}{\sqrt{x^2+4}}dx$ by applying integration method of trigonometric substitution using the substitution

$x=2\tan\left(\theta \right)$

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$x=2\tan\left(\theta \right)$

Learn how to solve problems step by step online. Find the integral int((x^3)/((x^2+4)^1/2))dx. We can solve the integral \int\frac{x^3}{\sqrt{x^2+4}}dx by applying integration method of trigonometric substitution using the substitution. Now, in order to rewrite d\theta in terms of dx, we need to find the derivative of x. We need to calculate dx, we can do that by deriving the equation above. Substituting in the original integral, we get. Factor the polynomial 4\tan\left(\theta \right)^2+4 by it's greatest common factor (GCF): 4.

$\frac{1}{3}\sqrt{\left(x^2+4\right)^{3}}-4\sqrt{x^2+4}+C_0$

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0
a
b
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f
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m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch