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Rewrite the fraction $\frac{v}{v^2-2v+1}$ inside the integral as the product of two functions: $v\frac{1}{v^2-2v+1}$
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$\int v\frac{1}{v^2-2v+1}dv$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int(v/(v^2-2v+1))dv. Rewrite the fraction \frac{v}{v^2-2v+1} inside the integral as the product of two functions: v\frac{1}{v^2-2v+1}. We can solve the integral \int v\frac{1}{v^2-2v+1}dv by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.