Final answer to the problem
Step-by-step Solution
Specify the solving method
Factor the trinomial $\left(x^2+x-6\right)$ finding two numbers that multiply to form $-6$ and added form $1$
Learn how to solve integrals by partial fraction expansion problems step by step online.
$\begin{matrix}\left(-2\right)\left(3\right)=-6\\ \left(-2\right)+\left(3\right)=1\end{matrix}$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((6x^2+22x+-23)/((2x-1)(x^2+x+-6)))dx. Factor the trinomial \left(x^2+x-6\right) finding two numbers that multiply to form -6 and added form 1. Thus. Rewrite the fraction \frac{6x^2+22x-23}{\left(2x-1\right)\left(x-2\right)\left(x+3\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(2x-1\right)\left(x-2\right)\left(x+3\right).