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Rewrite the fraction $\frac{6x^2+22x-23}{\left(2x-1\right)\left(x^2+x-6\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{6x^2+22x-23}{\left(2x-1\right)\left(x^2+x-6\right)}=\frac{A}{2x-1}+\frac{Bx+C}{x^2+x-6}$
Learn how to solve differential calculus problems step by step online. Find the integral int((6x^2+22x+-23)/((2x-1)(x^2+x+-6)))dx. Rewrite the fraction \frac{6x^2+22x-23}{\left(2x-1\right)\left(x^2+x-6\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(2x-1\right)\left(x^2+x-6\right). Multiplying polynomials. Simplifying.