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Find the integral $\int\frac{16x^2-48x+15}{x\left(2x-1\right)\left(x-3\right)}dx$

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 Solution

 Videos

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Algebra 2 - Solve for x by combining like terms first, (8x + 1) + (3x - 2) = 32

https://www.youtube.com/watch?v=22iNpGy5vn4

Algebra 2 - Tutoring Alg 2 Subtracting two polynomials (4m^2-6m+5) - (6m^2+3m-1)

https://www.youtube.com/watch?v=6pb0D5AQCK4

Algebra 1 - How to simplify the subtraction of two polynomials (2a^2+8a+4) - (a^2-3)

https://www.youtube.com/watch?v=HDkv1Ty8BSQ

Definite integral of rational function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=4WJUEXIksH0

_-substitution: definite integral of exponential function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=1ct7LUx23io

 Function Plot

Plotting: $5\ln\left(x\right)+\frac{7}{2}\ln\left(2x-1\right)-3\ln\left(x-3\right)+C_0$

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7

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9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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