$2y^3-5y^3$
$18\cdot19$
$sin3u\:=\:sin\:u\:\left(3\:-\:4sin^2u\right)$
$x^3-3x^2$
$\int_{-4}^2\left(-4x^2-3x^3+4\right)dx$
$16^1$
$\left(6+\left(x^2+5\right)^4\right)^3$
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