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Rewrite the fraction $\frac{1}{\sqrt{x^2}+2x-3}$ inside the integral as the product of two functions: $1\left(\frac{1}{\sqrt{x^2}+2x-3}\right)$
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$\int1\left(\frac{1}{\sqrt{x^2}+2x-3}\right)dx$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int(1/(x^2^1/2+2x+-3))dx. Rewrite the fraction \frac{1}{\sqrt{x^2}+2x-3} inside the integral as the product of two functions: 1\left(\frac{1}{\sqrt{x^2}+2x-3}\right). We can solve the integral \int1\left(\frac{1}{\sqrt{x^2}+2x-3}\right)dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.