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Simplify the expression $\frac{\left(\sqrt[6]{\left(6a^2+b^2+11ab-10b^2\right)^{5}}\right)^2\left(3ab+2\right)^{-\frac{5}{3}}}{\left(4b-10\right)^{\frac{5}{3}}}$

Step-by-step Solution

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Final answer to the problem

$\frac{\sqrt[3]{\left(6a^2-9b^2+11ab\right)^{5}}}{\sqrt[3]{\left(4b-10\right)^{5}}\sqrt[3]{\left(3ab+2\right)^{5}}}$
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Step-by-step Solution

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Divide $5$ by $3$

$\frac{\left(\sqrt[6]{\left(6a^2+b^2+11ab-10b^2\right)^{5}}\right)^2\left(3ab+2\right)^{-\frac{5}{3}}}{\sqrt[3]{\left(4b-10\right)^{5}}}$

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$\frac{\left(\sqrt[6]{\left(6a^2+b^2+11ab-10b^2\right)^{5}}\right)^2\left(3ab+2\right)^{-\frac{5}{3}}}{\sqrt[3]{\left(4b-10\right)^{5}}}$

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Learn how to solve simplification of algebraic expressions problems step by step online. Simplify the expression ((6a^2+b^211ab-10b^2)^5/6^2(3ab+2)^(-5/3))/((4b-10)^(5/3)). Divide 5 by 3. Divide -5 by 3. Combining like terms b^2 and -10b^2. Simplify \left(\sqrt[6]{\left(6a^2-9b^2+11ab\right)^{5}}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals \frac{5}{6} and n equals 2.

Final answer to the problem

$\frac{\sqrt[3]{\left(6a^2-9b^2+11ab\right)^{5}}}{\sqrt[3]{\left(4b-10\right)^{5}}\sqrt[3]{\left(3ab+2\right)^{5}}}$

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FactorFactor by completing the squareFind the integralFind the derivativeSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $\frac{\sqrt[3]{\left(6a^2-9b^2+11ab\right)^{5}}}{\sqrt[3]{\left(4b-10\right)^{5}}\sqrt[3]{\left(3ab+2\right)^{5}}}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Simplification of algebraic expressions

The simplification of algebraic expressions consists in rewriting a long and complex expression in an equivalent, but much simpler expression. This simplification can be accomplished through the combined use of arithmetic and algebra rules.

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