Final answer to the problem
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- Factor
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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Since $\sin$ is the reciprocal of $\csc$, $\frac{1}{\sin\left(2x\right)^2\cos\left(2x\right)^4}$ is equivalent to $\frac{\csc\left(2x\right)^2}{\cos\left(2x\right)^4}$
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$\frac{1\csc\left(2x\right)^2}{\cos\left(2x\right)^4}$
Learn how to solve factor problems step by step online. Factor the expression 1/(sin(2x)^2cos(2x)^4). Since \sin is the reciprocal of \csc, \frac{1}{\sin\left(2x\right)^2\cos\left(2x\right)^4} is equivalent to \frac{\csc\left(2x\right)^2}{\cos\left(2x\right)^4}. Any expression multiplied by 1 is equal to itself. Since \cos is the reciprocal of \sec, \frac{\csc\left(2x\right)^2}{\cos\left(2x\right)^4} is equivalent to \csc\left(2x\right)^2\sec\left(2x\right)^4.