$y^2=4x^3+22x^2$
$2-x<-6$
$\left(b-4\right)^3$
$9a^3b^2+12a^4b$
$15n^3-40n^2$
$\frac{\sqrt[3]{x}}{\left(x^3+1\right)}$
$\frac{1}{1-\sen^{2}\theta}=1+\tan^{2}\theta$
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