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Exercise

$x^2+x+\frac{1}{4}$

Limit of this function

$\lim_{x\to0}\left(x^2+x+\frac{1}{4}\right)=\frac{1}{4}$
See step-by-step solution

Derivative of this function

$\frac{d}{dx}\left(x^2+x+\frac{1}{4}\right)=2x+1$
See step-by-step solution

Integral of this function

$\int\left(x^2+x+\frac{1}{4}\right)dx=\frac{x^{3}}{3}+\frac{1}{2}x^2+\frac{1}{4}x+C_0$
See step-by-step solution

Try other ways to solve this exercise

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  • Write in simplest form
  • Solve by quadratic formula (general formula)
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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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