Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Solve by quadratic formula (general formula)
- Solve for x
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Find break even points
- Load more...
Find the roots of the equation using the Quadratic Formula
Learn how to solve equations problems step by step online.
$\frac{\frac{x^3-1}{x^3-2x^2-3x}\left(x+1\right)}{x^2+x-2}+\frac{x^2+x+1}{6x+x^2-x^3}=0$
Learn how to solve equations problems step by step online. Find the roots of ((x^3-1)/(x^3-2x^2-3x)(x+1))/(x^2+x+-2)+(x^2+x+1)/(6x+x^2-x^3). Find the roots of the equation using the Quadratic Formula. Multiplying the fraction by x+1. Divide fractions \frac{\frac{\left(x^3-1\right)\left(x+1\right)}{x^3-2x^2-3x}}{x^2+x-2} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. Factor the trinomial \left(x^2+x-2\right) finding two numbers that multiply to form -2 and added form 1.