$3 ^ { \prime } ( - 3 ) 3 = 6$
$12b^6+6^3-18^2$
$\left(\frac{3}{2}-\frac{x}{4}\right)^2$
$\frac{dy}{dx}=\left(4x^3+2\right)^3$
$\left(x^2-x+1\right)\left(x^2-2\right)$
$+7a-8b+5c-7a+5a-6b-8a+12b$
$\int_0^{\sqrt{5}}\left(xe^{8-2x^2}-x\right)dx$
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