Step-by-step Solution

Factor the expression $121+198x^6+81x^{12}$

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$\left(9x^{6}+11\right)^{2}$

Step-by-step Solution

Problem to solve:

$factor\left(121+198x^6+81x^{12}\right)$

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1

The trinomial $121+198x^6+81x^{12}$ is a perfect square trinomial, because it's discriminant is equal to zero

$\Delta=b^2-4ac=198^2-4\left(81\right)\left(121\right) = 0$

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$\Delta=b^2-4ac=198^2-4\left(81\right)\left(121\right) = 0$

Learn how to solve factorization problems step by step online. Factor the expression 121+198x^6+81x^12. The trinomial 121+198x^6+81x^{12} is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial.

$\left(9x^{6}+11\right)^{2}$
SnapXam A2

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7
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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$factor\left(121+198x^6+81x^{12}\right)$