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# Solve the equation $1+\frac{-\left(2u-3\right)}{4}=\frac{2-5u}{3}-3u$

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##  Final answer to the problem

$u=-\frac{\frac{13}{3}}{\frac{50}{3}}$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Solve for u
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
1

Simplify the product $-(2u-3)$

$1+\frac{-2u+3}{4}=\frac{2-5u}{3}-3u$

Learn how to solve one-variable linear equations problems step by step online.

$1+\frac{-2u+3}{4}=\frac{2-5u}{3}-3u$

Learn how to solve one-variable linear equations problems step by step online. Solve the equation 1+(-(2u-3))/4=(2-5u)/3-3u. Simplify the product -(2u-3). We need to isolate the dependent variable , we can do that by simultaneously subtracting 1 from both sides of the equation. Combine all terms into a single fraction with 3 as common denominator. Subtract the values 2 and -3.

##  Final answer to the problem

$u=-\frac{\frac{13}{3}}{\frac{50}{3}}$

$u=-0.26$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: One-variable linear equations

Algebraic equations that have just one variable.