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Step-by-step Solution

Solve the product power (4/3x^2*y^3)^3(3/(16x^5))^2

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Answer

$\frac{64}{27}x^{6}y^{9}\left(\frac{\frac{9}{256}}{x^{10}}\right)$

Step-by-step explanation

Problem to solve:

$\left(\frac{4}{3} x^2 y^3\right)^3\left(\frac{3}{16x^5}\right)^2$
1

Divide $4$ by $3$

$\left(\frac{4}{3}x^2y^3\right)^3\left(\frac{3}{16x^5}\right)^2$
2

The power of a product is equal to the product of it's factors raised to the same power

$\frac{64}{27}x^{6}y^{9}\left(\frac{3}{16x^5}\right)^2$

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Answer

$\frac{64}{27}x^{6}y^{9}\left(\frac{\frac{9}{256}}{x^{10}}\right)$
$\left(\frac{4}{3} x^2 y^3\right)^3\left(\frac{3}{16x^5}\right)^2$

Main topic:

Exponent properties

Time to solve it:

~ 0.83 seconds

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