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Find the integral $\int\frac{1}{\sqrt{\left(1+x^2\right)^3}}dx$

Step-by-step Solution

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Final Answer

$\frac{x}{\sqrt{1+x^2}}+C_0$
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Step-by-step Solution

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1

Simplify $\sqrt{\left(1+x^2\right)^3}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $3$ and $n$ equals $\frac{1}{2}$

$\int\frac{1}{\sqrt{\left(1+x^2\right)^{3}}}dx$
2

We can solve the integral $\int\frac{1}{\sqrt{\left(1+x^2\right)^{3}}}dx$ by applying integration method of trigonometric substitution using the substitution

$x=\tan\left(\theta \right)$
3

Now, in order to rewrite $d\theta$ in terms of $dx$, we need to find the derivative of $x$. We need to calculate $dx$, we can do that by deriving the equation above

$dx=\sec\left(\theta \right)^2d\theta$
4

Substituting in the original integral, we get

$\int\frac{\sec\left(\theta \right)^2}{\sqrt{\left(1+\tan\left(\theta \right)^2\right)^{3}}}d\theta$
5

Applying the trigonometric identity: $1+\tan\left(\theta \right)^2 = \sec\left(\theta \right)^2$

$\int\frac{\sec\left(\theta \right)^2}{\sqrt{\left(\sec\left(\theta \right)^2\right)^{3}}}d\theta$
Why is tan(x)^2+1 = sec(x)^2 ?
6

Simplify $\sqrt{\left(\sec\left(\theta \right)^2\right)^{3}}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $2$ and $n$ equals $\frac{3}{2}$

$\int\frac{\sec\left(\theta \right)^2}{\sec\left(\theta \right)^{3}}d\theta$
7

Simplify the fraction by $\sec\left(\theta \right)$

$\int\frac{1}{\sec\left(\theta \right)}d\theta$
8

Applying the trigonometric identity: $\displaystyle\frac{1}{\sec(\theta)}=\cos(\theta)$

$\int\cos\left(\theta \right)d\theta$
9

Apply the integral of the cosine function: $\int\cos(x)dx=\sin(x)$

$\sin\left(\theta \right)$
10

Express the variable $\theta$ in terms of the original variable $x$

$\frac{x}{\sqrt{1+x^2}}$
11

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$\frac{x}{\sqrt{1+x^2}}+C_0$

Final Answer

$\frac{x}{\sqrt{1+x^2}}+C_0$

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Function Plot

Plotting: $\frac{x}{\sqrt{1+x^2}}+C_0$

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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