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Expand the fraction $\frac{2u-1}{4u^2-1}$ into $2$ simpler fractions with common denominator $4u^2-1$
Learn how to solve integrals of rational functions problems step by step online.
$\int\left(\frac{2u}{4u^2-1}+\frac{-1}{4u^2-1}\right)du$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int((2u-1)/(4u^2-1))du. Expand the fraction \frac{2u-1}{4u^2-1} into 2 simpler fractions with common denominator 4u^2-1. Simplify the expression inside the integral. The integral 2\int\frac{u}{4u^2-1}du results in: \frac{1}{4}\ln\left(2u+1\right)+\frac{1}{4}\ln\left(2u-1\right). Gather the results of all integrals.