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\int\frac{x}{\sqrt{16-x^2}}dx

Integral of x/((16-x^2)^0.5)

Answer

$-\sqrt{16-x^2}+C_0$

Step-by-step explanation

Problem to solve:

$\int\frac{x}{\sqrt{16-x^2}}dx$
1

Solve the integral $\int\frac{x}{\sqrt{16-x^2}}dx$ by trigonometric substitution using the substitution

$\begin{matrix}x=4\sin\left(\theta\right) \\ dx=4\cos\left(\theta\right)d\theta\end{matrix}$

Unlock this step-by-step solution!

Answer

$-\sqrt{16-x^2}+C_0$

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$\int\frac{x}{\sqrt{16-x^2}}dx$

Main topic:

Integration by trigonometric substitution

Used formulas:

5. See formulas

Time to solve it:

~ 0.68 seconds