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Integral of 1/(x^2(4-1x^2)^0.5)

\int\frac{1}{x^2\sqrt{4-x^2}}dx

Step by step solution

Problem

$\int\frac{1}{x^2\sqrt{4-x^2}}dx$

Show full step-by-step solution

Answer

$\frac{1}{4}\int\frac{\frac{d}{d\theta}\left(2\sin\left(\theta\right)\right)}{\sin\left(\theta\right)^2\cos\left(\theta\right)}d\theta$
$\int\frac{1}{x^2\sqrt{4-x^2}}dx$

Main topic:

Integration by trigonometric substitution

Used formulas:

0

Time to solve it:

0.32 seconds