Quotient of powers Calculator
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$\pi ^{\tan\left(\frac{n^2+1}{2n^2}\right)}$
2
Taking out the constant $2$ from the fraction's denominator
$\pi ^{\tan\left(\frac{1}{2}\cdot\frac{1+n^2}{n^2}\right)}$
3
Applying the tangent identity: $\displaystyle\tan\left(\theta\right)=\frac{\sin\left(\theta\right)}{\cos\left(\theta\right)}$
$\pi ^{\left(\frac{\sin\left(\frac{1}{2}\cdot\frac{1+n^2}{n^2}\right)}{\cos\left(\frac{1}{2}\cdot\frac{1+n^2}{n^2}\right)}\right)}$
4
Multiplying the fraction and term
$\pi ^{\left(\frac{\sin\left(\frac{\frac{1}{2}\left(1+n^2\right)}{n^2}\right)}{\cos\left(\frac{\frac{1}{2}\left(1+n^2\right)}{n^2}\right)}\right)}$
5
Apply the formula: $\frac{\sin\left(x\right)}{\cos\left(x\right)}$$=\tan\left(x\right)$, where $x=\frac{\frac{1}{2}\left(1+n^2\right)}{n^2}$
$\pi ^{\tan\left(\frac{\frac{1}{2}\left(1+n^2\right)}{n^2}\right)}$
6
Applying the tangent identity: $\displaystyle\tan\left(\theta\right)=\frac{\sin\left(\theta\right)}{\cos\left(\theta\right)}$
$\pi ^{\left(\frac{\sin\left(\frac{\frac{1}{2}\left(1+n^2\right)}{n^2}\right)}{\cos\left(\frac{\frac{1}{2}\left(1+n^2\right)}{n^2}\right)}\right)}$