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Limits of Exponential Functions Calculator

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1

Solved example of limits of exponential functions

$\lim_{x\to0}\left(1+3sinx\right)^{\frac{1}{x}}$
2

Rewrite the limit using the identity: $a^x=e^{x\ln\left(a\right)}$

$\lim_{x\to0}\left(e^{\frac{1}{x}\ln\left(1+3\sin\left(x\right)\right)}\right)$
3

Multiplying the fraction by $\ln\left(1+3\sin\left(x\right)\right)$

$\lim_{x\to0}\left(e^{\frac{\ln\left(1+3\sin\left(x\right)\right)}{x}}\right)$

4

Apply the power rule of limits: $\displaystyle{\lim_{x\to a}f(x)^{g(x)} = \lim_{x\to a}f(x)^{\displaystyle\lim_{x\to a}g(x)}}$

${\left(\lim_{x\to0}\left(e\right)\right)}^{\lim_{x\to0}\left(\frac{\ln\left(1+3\sin\left(x\right)\right)}{x}\right)}$
5

The limit of a constant is just the constant

$e^{\lim_{x\to0}\left(\frac{\ln\left(1+3\sin\left(x\right)\right)}{x}\right)}$

Plug in the value $0$ into the limit

$\frac{\ln\left(1+3\sin\left(0\right)\right)}{0}$

The sine of $0$ equals $0$

$\frac{\ln\left(1\right)}{0}$

Calculating the natural logarithm of $1$

$\frac{0}{0}$
6

If we directly evaluate the limit $\lim_{x\to 0}\left(\frac{\ln\left(1+3\sin\left(x\right)\right)}{x}\right)$ as $x$ tends to $0$, we can see that it gives us an indeterminate form

$\frac{0}{0}$
7

We can solve this limit by applying L'Hôpital's rule, which consists of calculating the derivative of both the numerator and the denominator separately

$\lim_{x\to 0}\left(\frac{\frac{d}{dx}\left(\ln\left(1+3\sin\left(x\right)\right)\right)}{\frac{d}{dx}\left(x\right)}\right)$

Find the derivative of the numerator

$\frac{d}{dx}\left(\ln\left(1+3\sin\left(x\right)\right)\right)$

The derivative of the natural logarithm of a function is equal to the derivative of the function divided by that function. If $f(x)=ln\:a$ (where $a$ is a function of $x$), then $\displaystyle f'(x)=\frac{a'}{a}$

$\frac{1}{1+3\sin\left(x\right)}\frac{d}{dx}\left(1+3\sin\left(x\right)\right)$

The derivative of a sum of two or more functions is the sum of the derivatives of each function

$\frac{1}{1+3\sin\left(x\right)}\left(\frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(3\sin\left(x\right)\right)\right)$

The derivative of the constant function ($1$) is equal to zero

$\frac{1}{1+3\sin\left(x\right)}\frac{d}{dx}\left(3\sin\left(x\right)\right)$

The derivative of a function multiplied by a constant ($3$) is equal to the constant times the derivative of the function

$3\left(\frac{1}{1+3\sin\left(x\right)}\right)\frac{d}{dx}\left(\sin\left(x\right)\right)$

The derivative of the sine of a function is equal to the cosine of that function times the derivative of that function, in other words, if ${f(x) = \sin(x)}$, then ${f'(x) = \cos(x)\cdot D_x(x)}$

$\frac{3\cos\left(x\right)}{1+3\sin\left(x\right)}$

Find the derivative of the denominator

$\frac{d}{dx}\left(x\right)$

The derivative of the linear function is equal to $1$

$1$

Any expression divided by one ($1$) is equal to that same expression

$e^{\lim_{x\to0}\left(\frac{3\cos\left(x\right)}{1+3\sin\left(x\right)}\right)}$
8

After deriving both the numerator and denominator, the limit results in

$e^{\lim_{x\to0}\left(\frac{3\cos\left(x\right)}{1+3\sin\left(x\right)}\right)}$
9

Evaluate the limit $\lim_{x\to0}\left(\frac{3\cos\left(x\right)}{1+3\sin\left(x\right)}\right)$ by replacing all occurrences of $x$ by $0$

$e^{\frac{3\cos\left(0\right)}{1+3\sin\left(0\right)}}$

The sine of $0$ equals $0$

$e^{\frac{3\cos\left(0\right)}{1+3\cdot 0}}$

Multiply $3$ times $0$

$e^{\frac{3\cos\left(0\right)}{1+0}}$

Add the values $1$ and $0$

$e^{\frac{3\cos\left(0\right)}{1}}$

The cosine of $0$ equals $1$

$e^{\frac{3\cdot 1}{1}}$

Multiply $3$ times $1$

$e^{\frac{3}{1}}$

Divide $3$ by $1$

$e^{3}$
10

Simplifying, we get

$e^{3}$
11

Calculate the power $e^{3}$

$e^{3}$

Final Answer

$e^{3}$

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