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Inverse trigonometric functions differentiation


Definition

Describes how to find the derivative of the inverse of the trigonometric functions sine, cosine, tangent, etc.

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Problems Solved

Find the derivative $\frac{d}{dx}\left(\frac{5xy}{1+y^2}=\arctan\left(y\right)\right)$
$\frac{d}{dx}\left(sec^{-1}\right)\left(5x^4\right)$
$\frac{d}{dx}\arctan x^2$
$\frac{d}{dx}arccot\sqrt{x}$
Find the derivative $\frac{dy}{dx}\left(y=x\tan^{-1}\left(2x\right)\right)$
$\frac{d}{dx}ln\left(\arctan\left(3x^5\right)\right)$
$\frac{d}{dx}\tan^{-1}\ln\left(4x\right)$
Find the derivative $\frac{dy}{dx}\left(y=cot^{-1}\sqrt{7x}\right)$

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Related Topics

Implicit Differentiation
Logarithmic Differentiation
Higher-order derivatives

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