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$x^2-4x=y^2-6y+6$
Learn how to solve differential calculus problems step by step online. Solve the quadratic equation x^2-4x-y^26y+-6=0. Group the terms of the equation. Factor the polynomial x^2-4x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -4. Now, we can factor x^2+-4x+4 as a squared binomial of the form \left(x+\frac{b}{2}\right)^2. The square root of 4 is .