Final answer to the problem
Step-by-step Solution
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- Solve for x
- Find the roots
- Solve by factoring
- Solve by completing the square
- Solve by quadratic formula (general formula)
- Find break even points
- Find the discriminant
- Exact Differential Equation
- Linear Differential Equation
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Rewrite the equation
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$x^2-12x-58=0$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2-12x=58. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-12 and c=-58. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).