# Step-by-step Solution

## Solve the quadratic equation $32x^2-18x-17=0$

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### Videos

$x=1.0625,\:x=-0.5$

## Step-by-step Solution

Problem to solve:

$32x^2-18\cdot x-17=0$

Choose the solving method

1

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=32$, $b=-18$ and $c=-17$. Then substitute the values of the coefficients of the equation in the quadratic formula:

• $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{18\pm 50}{64}$

Learn how to solve quadratic equations problems step by step online.

$x=\frac{18\pm 50}{64}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 32x^2-18x-17=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=32, b=-18 and c=-17. Then substitute the values of the coefficients of the equation in the quadratic formula:<ul><li>\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</li></ul>. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 18 and -50. Add the values 18 and 50.

$x=1.0625,\:x=-0.5$
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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$32x^2-18\cdot x-17=0$