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Solve the quadratic equation $x^2+6x-7=0$

Step-by-step Solution

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Final Answer

$x=1,\:x=-7$
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Step-by-step Solution

Problem to solve:

$x^2+6x-7=0$

Specify the solving method

1

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=1$, $b=6$ and $c=-7$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-6+\pm 8}{2}$
2

To obtain the two solutions, divide the equation in two equations, one when $\pm$ is positive ($+$), and another when $\pm$ is negative ($-$)

$x=\frac{-6+8}{2},\:x=\frac{-6-8}{2}$

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$x=\frac{-6+\pm 8}{2}$

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Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+6x-7=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=6 and c=-7. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Subtract the values 8 and -6. Subtract the values -6 and -8.

Final Answer

$x=1,\:x=-7$

Explore different ways to solve this problem

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1
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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

$x^2+6x-7=0$

Main topic:

Quadratic equations

Used formulas:

1. See formulas

Time to solve it:

~ 0.03 s