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Find the break even points of the expression $a^2+\frac{-ab^2}{a}$

Step-by-step Solution

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Final answer to the problem

$a=b,\:a=-b$
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Step-by-step Solution

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Find the break even points of the polynomial $a^2+\frac{-ab^2}{a}$ by putting it in the form of an equation and then set it equal to zero

$a^2+\frac{-ab^2}{a}=0$

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$a^2+\frac{-ab^2}{a}=0$

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Learn how to solve quadratic equations problems step by step online. Find the break even points of the expression a^2+(-ab^2)/a. Find the break even points of the polynomial a^2+\frac{-ab^2}{a} by putting it in the form of an equation and then set it equal to zero. Simplify the fraction \frac{-ab^2}{a} by a. We need to isolate the dependent variable , we can do that by simultaneously subtracting -b^2 from both sides of the equation. Multiply -1 times -1.

Final answer to the problem

$a=b,\:a=-b$

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Plotting: $a^2+\frac{-ab^2}{a}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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