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Find the break even points of the polynomial $4\left(x+7\right)^2+6\left(2x-5\right)^2-3\left(x^2+7x-2\right)$ by putting it in the form of an equation and then set it equal to zero
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$4\left(x+7\right)^2+6\left(2x-5\right)^2-3\left(x^2+7x-2\right)=0$
Learn how to solve integrals of exponential functions problems step by step online. Find the break even points of the expression 4(x+7)^2+6(2x-5)^2-3(x^2+7x+-2). Find the break even points of the polynomial 4\left(x+7\right)^2+6\left(2x-5\right)^2-3\left(x^2+7x-2\right) by putting it in the form of an equation and then set it equal to zero. Multiply the single term -3 by each term of the polynomial \left(x^2+7x-2\right). Expand \left(2x-5\right)^2. The power of a product is equal to the product of it's factors raised to the same power.