Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Find the roots
- Solve for x
- Solve by factoring
- Solve by completing the square
- Solve by quadratic formula (general formula)
- Find break even points
- Find the discriminant
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
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Find the roots of the polynomial $4\left(x+7\right)^2+6\left(2x-5\right)^2-3\left(x^2+7x-2\right)$ by putting it in the form of an equation and then set it equal to zero
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$4\left(x+7\right)^2+6\left(2x-5\right)^2-3\left(x^2+7x-2\right)=0$
Learn how to solve equations problems step by step online. Find the roots of 4(x+7)^2+6(2x-5)^2-3(x^2+7x+-2). Find the roots of the polynomial 4\left(x+7\right)^2+6\left(2x-5\right)^2-3\left(x^2+7x-2\right) by putting it in the form of an equation and then set it equal to zero. Multiply the single term -3 by each term of the polynomial \left(x^2+7x-2\right). Expand \left(2x-5\right)^2. The power of a product is equal to the product of it's factors raised to the same power.