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Factor the trinomial $23x^2-68x-3$ of the form $ax^2+bx+c$, first, make the product of $23$ and $-3$
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$\left(23\right)\left(-3\right)=-69$
Learn how to solve product rule of differentiation problems step by step online. Solve the quadratic equation 23x^2-68x+-3=0. Factor the trinomial 23x^2-68x-3 of the form ax^2+bx+c, first, make the product of 23 and -3. Now, find two numbers that multiplied give us -69 and add up to -68. Rewrite the original expression. Factor 23x^2-69x+x-3 by the greatest common divisor 23.