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Factor the trinomial $16x^2+10x-9$ of the form $ax^2+bx+c$, first, make the product of $16$ and $-9$
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$\left(16\right)\left(-9\right)=-144$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 16x^2+10x+-9=0. Factor the trinomial 16x^2+10x-9 of the form ax^2+bx+c, first, make the product of 16 and -9. Now, find two numbers that multiplied give us -144 and add up to 10. Rewrite the original expression. Factor 16x^2+18x-8x-9 by the greatest common divisor 8.