Final Answer
$\left(y-1\right)^2\left(y^2+y+1\right)^2\left(y+1\right)^2\left(\frac{3}{4}+\left(y-\frac{1}{2}\right)^2\right)^2-y^6\left(y^6-2\right)$
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Step-by-step Solution
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The power of a product is equal to the product of it's factors raised to the same power
$\left(y-1\right)^2\left(y^2+y+1\right)^2\left(y^3+1\right)^2-y^6\left(y^6-2\right)$
Learn how to solve factor problems step by step online.
$\left(y-1\right)^2\left(y^2+y+1\right)^2\left(y^3+1\right)^2-y^6\left(y^6-2\right)$
Learn how to solve factor problems step by step online. Factor the expression ((y-1)(y^2+y+1))^2(y^3+1)^2-y^6(y^6-2). The power of a product is equal to the product of it's factors raised to the same power. Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). The power of a product is equal to the product of it's factors raised to the same power. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2.
Final Answer
$\left(y-1\right)^2\left(y^2+y+1\right)^2\left(y+1\right)^2\left(\frac{3}{4}+\left(y-\frac{1}{2}\right)^2\right)^2-y^6\left(y^6-2\right)$