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Find the derivative of $\left(\left(y-1\right)\left(y^2+y+1\right)\right)^2\left(y^3+1\right)^2-y^6\left(y^6-2\right)$

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Final Answer

$2\left(y-1\right)\left(y^2+y+1\right)^2\left(y^3+1\right)^2+\left(y-1\right)^2\left(2\left(y^2+y+1\right)\left(2y+1\right)\left(y^3+1\right)^2+6\left(y^2+y+1\right)^2\left(y^3+1\right)y^{2}\right)-6y^{5}y^6+6\left(-y^6+2\right)y^{5}$
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Step-by-step Solution

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Simplifying

$\frac{d}{dy}\left(\left(\left(y-1\right)\left(y^2+y+1\right)\right)^2\left(y^3+1\right)^2+\left(-y^6+2\right)y^6\right)$

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$\frac{d}{dy}\left(\left(\left(y-1\right)\left(y^2+y+1\right)\right)^2\left(y^3+1\right)^2+\left(-y^6+2\right)y^6\right)$

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Learn how to solve problems step by step online. Find the derivative of ((y-1)(y^2+y+1))^2(y^3+1)^2-y^6(y^6-2). Simplifying. The power of a product is equal to the product of it's factors raised to the same power. The derivative of a sum of two or more functions is the sum of the derivatives of each function. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=\left(y-1\right)^2 and g=\left(y^2+y+1\right)^2\left(y^3+1\right)^2.

Final Answer

$2\left(y-1\right)\left(y^2+y+1\right)^2\left(y^3+1\right)^2+\left(y-1\right)^2\left(2\left(y^2+y+1\right)\left(2y+1\right)\left(y^3+1\right)^2+6\left(y^2+y+1\right)^2\left(y^3+1\right)y^{2}\right)-6y^{5}y^6+6\left(-y^6+2\right)y^{5}$

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Function Plot

Plotting: $2\left(y-1\right)\left(y^2+y+1\right)^2\left(y^3+1\right)^2+\left(y-1\right)^2\left(2\left(y^2+y+1\right)\left(2y+1\right)\left(y^3+1\right)^2+6\left(y^2+y+1\right)^2\left(y^3+1\right)y^{2}\right)-6y^{5}y^6+6\left(-y^6+2\right)y^{5}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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