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Rewrite the fraction $\frac{x^3}{\sqrt{x^2}+4}$ inside the integral as the product of two functions: $x^3\frac{1}{\sqrt{x^2}+4}$
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$\int_{0}^{2} x^3\frac{1}{\sqrt{x^2}+4}dx$
Learn how to solve differential calculus problems step by step online. Integrate the function (x^3)/(x^2^1/2+4) from 0 to 2. Rewrite the fraction \frac{x^3}{\sqrt{x^2}+4} inside the integral as the product of two functions: x^3\frac{1}{\sqrt{x^2}+4}. We can solve the integral \int x^3\frac{1}{\sqrt{x^2}+4}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.