$\sqrt{1+x^2}\left(\frac{dy}{dx}\right)=\frac{x}{y}\:\:\:\:\:\:y\left(0\right)=-3$
$m^2+10m$
$x^6-1000y^3$
$3x^3-6x+1\:x\:-2x^2+5$
$\left(x^4+3x^3+6\right)\left(2x-1\right)$
$\left(-5+8-11\right)\:\left(-2-8\right)$
$x^2-7x+10;\:x=1$
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