Final Answer
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Rewrite the fraction $\frac{2x^3-x}{\left(x^2-9\right)^2}$ in $2$ simpler fractions using partial fraction decomposition
Learn how to solve integrals by partial fraction expansion problems step by step online.
$\frac{2x^3-x}{\left(x^2-9\right)^2}=\frac{Ax+B}{x^2-9}+\frac{Cx+D}{\left(x^2-9\right)^{2}}$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((2x^3-x)/((x^2-9)^2))dx. Rewrite the fraction \frac{2x^3-x}{\left(x^2-9\right)^2} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D. The first step is to multiply both sides of the equation from the previous step by \left(x^2-9\right)^2. Multiplying polynomials. Simplifying.