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Factor the trinomial $x^2+x-6$ finding two numbers that multiply to form $-6$ and added form $1$
Learn how to solve integrals by partial fraction expansion problems step by step online.
$\begin{matrix}\left(-2\right)\left(3\right)=-6\\ \left(-2\right)+\left(3\right)=1\end{matrix}$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int(1/(x^2+x+-6))dx. Factor the trinomial x^2+x-6 finding two numbers that multiply to form -6 and added form 1. Thus. Rewrite the fraction \frac{1}{\left(x-2\right)\left(x+3\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x-2\right)\left(x+3\right).