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Rewrite the fraction $\frac{x^2}{\left(\sqrt{16-x}\right)^2}$ inside the integral as the product of two functions: $x^2\frac{1}{\left(\sqrt{16-x}\right)^2}$
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$\int x^2\frac{1}{\left(\sqrt{16-x}\right)^2}dx$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int((x^2)/((16-x)^1/2^2))dx. Rewrite the fraction \frac{x^2}{\left(\sqrt{16-x}\right)^2} inside the integral as the product of two functions: x^2\frac{1}{\left(\sqrt{16-x}\right)^2}. We can solve the integral \int x^2\frac{1}{\left(\sqrt{16-x}\right)^2}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.