Final Answer
Step-by-step Solution
Specify the solving method
Expand the fraction $\frac{3x-4}{x^2-4x}$ into $2$ simpler fractions with common denominator $x^2-4x$
Learn how to solve differential calculus problems step by step online.
$\int\left(\frac{3x}{x^2-4x}+\frac{-4}{x^2-4x}\right)dx$
Learn how to solve differential calculus problems step by step online. Find the integral int((3x-4)/(x^2-4x))dx. Expand the fraction \frac{3x-4}{x^2-4x} into 2 simpler fractions with common denominator x^2-4x. Simplify the expression inside the integral. Rewrite the expression \frac{x}{x^2-4x} inside the integral in factored form. We can solve the integral \int\frac{1}{x-4}dx by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that x-4 it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part.