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Expand the fraction $\frac{3x-4}{x^2-4x}$ into $2$ simpler fractions with common denominator $x^2-4x$
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$\int\left(\frac{3x}{x^2-4x}+\frac{-4}{x^2-4x}\right)dx$
Learn how to solve problems step by step online. Find the integral int((3x-4)/(x^2-4x))dx. Expand the fraction \frac{3x-4}{x^2-4x} into 2 simpler fractions with common denominator x^2-4x. Simplify the expression inside the integral. Rewrite the expression \frac{x}{x^2-4x} inside the integral in factored form. The integral 3\int\frac{1}{x-4}dx results in: 3\ln\left(x-4\right).