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Factor the trinomial $x^2+2x-8$ finding two numbers that multiply to form $-8$ and added form $2$
Learn how to solve integrals by partial fraction expansion problems step by step online.
$\begin{matrix}\left(-2\right)\left(4\right)=-8\\ \left(-2\right)+\left(4\right)=2\end{matrix}$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((1-3x)/(x^2+2x+-8))dx. Factor the trinomial x^2+2x-8 finding two numbers that multiply to form -8 and added form 2. Thus. Rewrite the fraction \frac{1-3x}{\left(x-2\right)\left(x+4\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x-2\right)\left(x+4\right).